Optimal. Leaf size=54 \[ \frac{2}{a d \sqrt{a+b \sec (c+d x)}}-\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d} \]
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Rubi [A] time = 0.0528239, antiderivative size = 54, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {3885, 51, 63, 207} \[ \frac{2}{a d \sqrt{a+b \sec (c+d x)}}-\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d} \]
Antiderivative was successfully verified.
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Rule 3885
Rule 51
Rule 63
Rule 207
Rubi steps
\begin{align*} \int \frac{\tan (c+d x)}{(a+b \sec (c+d x))^{3/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1}{x (a+x)^{3/2}} \, dx,x,b \sec (c+d x)\right )}{d}\\ &=\frac{2}{a d \sqrt{a+b \sec (c+d x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+x}} \, dx,x,b \sec (c+d x)\right )}{a d}\\ &=\frac{2}{a d \sqrt{a+b \sec (c+d x)}}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{-a+x^2} \, dx,x,\sqrt{a+b \sec (c+d x)}\right )}{a d}\\ &=-\frac{2 \tanh ^{-1}\left (\frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{a}}\right )}{a^{3/2} d}+\frac{2}{a d \sqrt{a+b \sec (c+d x)}}\\ \end{align*}
Mathematica [B] time = 0.387311, size = 128, normalized size = 2.37 \[ \frac{\sec (c+d x) \left (\sqrt{a \cos (c+d x)} \sqrt{a \cos (c+d x)+b} \left (\log \left (1-\frac{\sqrt{a \cos (c+d x)+b}}{\sqrt{a \cos (c+d x)}}\right )-\log \left (\frac{\sqrt{a \cos (c+d x)+b}}{\sqrt{a \cos (c+d x)}}+1\right )\right )+2 a \cos (c+d x)\right )}{a^2 d \sqrt{a+b \sec (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.039, size = 45, normalized size = 0.8 \begin{align*}{\frac{1}{d} \left ( -2\,{\frac{1}{{a}^{3/2}}{\it Artanh} \left ({\frac{\sqrt{a+b\sec \left ( dx+c \right ) }}{\sqrt{a}}} \right ) }+2\,{\frac{1}{a\sqrt{a+b\sec \left ( dx+c \right ) }}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.29228, size = 664, normalized size = 12.3 \begin{align*} \left [\frac{4 \, a \sqrt{\frac{a \cos \left (d x + c\right ) + b}{\cos \left (d x + c\right )}} \cos \left (d x + c\right ) +{\left (a \cos \left (d x + c\right ) + b\right )} \sqrt{a} \log \left (-8 \, a^{2} \cos \left (d x + c\right )^{2} - 8 \, a b \cos \left (d x + c\right ) - b^{2} + 4 \,{\left (2 \, a \cos \left (d x + c\right )^{2} + b \cos \left (d x + c\right )\right )} \sqrt{a} \sqrt{\frac{a \cos \left (d x + c\right ) + b}{\cos \left (d x + c\right )}}\right )}{2 \,{\left (a^{3} d \cos \left (d x + c\right ) + a^{2} b d\right )}}, \frac{{\left (a \cos \left (d x + c\right ) + b\right )} \sqrt{-a} \arctan \left (\frac{2 \, \sqrt{-a} \sqrt{\frac{a \cos \left (d x + c\right ) + b}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{2 \, a \cos \left (d x + c\right ) + b}\right ) + 2 \, a \sqrt{\frac{a \cos \left (d x + c\right ) + b}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{a^{3} d \cos \left (d x + c\right ) + a^{2} b d}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan{\left (c + d x \right )}}{\left (a + b \sec{\left (c + d x \right )}\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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